maths (f.1) @ gpjqem1的部落格

標題:

maths (f.1)

發問:

Solve the equation. 100y = 4100000 - 300(2y+150)

最佳解答:

100y = 4,100,000 - 300(2y+150) 100y = 4,100,000 - 600y - 45,000 700y = 4,100,000 - 45,000 700y = 4,055,000 y = 5792.86 (to 2 d.p)

其他解答:

100y=4100000 - 300(2y+150) 100y=4100000 - 300(2y+150) 100y=4100000 - 600y - 45000 100y+600y=4100000 - 45000 700y=4055000 y=4055000/700 y=5792.857(correct to 3 decimal place)|||||100y = 100 (41000 - 3 (2y+150)) y = 41000 -6y -450 7y = 40550 y = 5792.86 (corr. to 2d.p.)|||||100y = 4100000 - 300(2y+150) 100y = 4100000 - 600y - 45000 100y +600y = 4100000 - 45000 700y = 4055000 y=5792.8571