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calculate the internal energy and enthalpy changes that occur when air is changed from an initial state of 40(°F) and 10(atm) , were its molar volume is 36.49(ft)3 (lb mole)-1, to a final state of 140(°F) and 1(atm) , assume for air that PV/T is constant and that cv=5 and cp=7(Btu)(lb mole) -1... 顯示更多 calculate the internal energy and enthalpy changes that occur when air is changed from an initial state of 40(°F) and 10(atm) , were its molar volume is 36.49(ft)3 (lb mole)-1, to a final state of 140(°F) and 1(atm) , assume for air that PV/T is constant and that cv=5 and cp=7(Btu)(lb mole) -1 (°F) -1 R=0.73 atm ft3/lb mole °R

最佳解答:

internal energy change(△U) = ∫nCvdT n = ? 用初始狀態算 PV = nRT 10 36.49 = n 0.73 ( 492+40 ) n = 0.94 ∴△U = ∫nCvdT = nCv( T(final)-T(initial) ) = 0.94 5 ( 140 - 40 ) = 470 atm ft3 enthalpy changes(△H) = ∫nCpdT (△H) = ∫nCpdT = nCp( T(final)-T(initial) ) = 0.94 7 ( 140 - 40 ) = 658 atm ft3

其他解答:6FE1C172E25AFD66