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Find(i)the maximum error (ii)the relative error (iii)the precentage error of the following measurements: (a)5.6cm correct to the nearest mm (b)23.7kg correct to the nearest 100g 更新: plx help me......

最佳解答:

ai)maximum absoulte error = 1 / 2 X correct to the nearest = 1 / 2 X 1 mm = 0.5 mm ii)Since 1 cm = 10mm, 5.6cm = 5.6 X 10 = 56mm maximum relative error = maximum absoulte error / measured value = 0.5 / 56 = 5 / 560 = 1 / 112 iii)maximum percentage error = maximum relative error X 100% = 1 / 112 X 100% = 0.9% (correct to the nearest 0.1%) bi)maximum absoulte error = 1 / 2 X correct to the nearest = 1 / 2 X 100 g = 50g ii)Since 1 kg = 1000g, 23.7kg = (23.7 X 1000)g = 23700g maximum relative error = maximum absoulte error / measured value = 50 / 23700 = 1 / 474 iii)maximum percentage error = maximum relative error X 100% = 1 / 474 X 100% = 0.2% (correct to the nearest 0.1%)

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